Hardy–Weinberg equilibrium
From the incidence of an autosomal recessive disease, estimates allele and carrier frequencies in the population and a couple’s risk of an affected child in each pregnancy.
Calculate with transparency
Check the population, units and version. The result shows the formula or classification; it does not make an automatic treatment decision.
Preparing the form…
- Check the method
- Enter the data
- Check the result
Method · Limits of application
Hardy–Weinberg 1908: p²+2pq+q²; autosomal recessive inheritance; unaffected sibling 2/3; couple risk ×1/4
The population calculation assumes an autosomal locus with two alleles in Hardy–Weinberg equilibrium; random mating and an ideally very large population are assumptions, not outputs of the calculation. Using q² as disease frequency requires agreement with the recessive model considered. A familial risk of 25% assumes two carrier parents; the 2/3 for an unaffected sibling is a conditional probability in that setting. Do not apply these relationships to every genetic disease or interpret them as an individual diagnosis.
Conditions of use
Check the population, units, inclusion and exclusion criteria, and version in the original source. A result alone does not establish a diagnosis, discharge decision or prescription.
Documented parameters
- Disease frequency: 1 affected person per · births
- Partner 1
- Partner 2
5/5 reference cases checked. Numerical tests are not clinical validation.
Relationship with cancer research
Support for research — context required
A population genetics model. Using it in cancer research requires appropriate population assumptions; it does not by itself estimate hereditary cancer risk.
Applications: Genomics · Epidemiology